2018~2019/Level 2
숫자의 표현 [Python3]
전기도둑
2018. 10. 3. 19:48
1 2 3 4 5 6 7 8 9 10 11 12 13 | def solution(n): answer = 0 for i in range(1,n+1): s=0 while s<n: s+=i i+=1 if s==n: answer+=1 return answer |