2018~2019/Level 2
전화번호 목록 [Python3]
전기도둑
2018. 10. 1. 22:53
1 2 3 4 5 6 7 8 9 10 11 | def solution(phone_book): answer = True phone_book.sort(); for i in range(1, len(phone_book)): number = phone_book[i]; if number.find(phone_book[0]) != -1: answer = False; return answer |