2018~2019/Level 2

전화번호 목록 [Python3]

전기도둑 2018. 10. 1. 22:53
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def solution(phone_book):
    answer = True
    phone_book.sort();

    for i in range(1, len(phone_book)):
        number = phone_book[i];
        if number.find(phone_book[0]) != -1:
            answer = False;

    return answer